1/3(x-4)+6=2/3(2x-1)+2

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Solution for 1/3(x-4)+6=2/3(2x-1)+2 equation: 



1/3(x-4)+6=2/3(2x-1)+2

We move all terms to the left:

1/3(x-4)+6-(2/3(2x-1)+2)=0



Domain of the equation: 3(x-4)!=0

x∈R





Domain of the equation: 3(2x-1)+2)!=0

x∈R



We calculate fractions


(3x2/(3(x-4)*3(2x-1))+(-6xx/(3(x-4)*3(2x-1))+6=0

We can not solve this equation

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