3(5z-1)-4(4Z-3)=(15z-3)-(16z-12)

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Solution for 3(5z-1)-4(4Z-3)=(15z-3)-(16z-12) equation: 



3(5z-1)-4(4-3)=(15z-3)-(16z-12)

We move all terms to the left:

3(5z-1)-4(4-3)-((15z-3)-(16z-12))=0

We add all the numbers together, and all the variables

3(5z-1)-((15z-3)-(16z-12))-41=0

We multiply parentheses

15z-((15z-3)-(16z-12))-3-41=0



We calculate terms in parentheses: -((15z-3)-(16z-12)), so:

(15z-3)-(16z-12)

We get rid of parentheses

15z-16z-3+12

We add all the numbers together, and all the variables

-1z+9

Back to the equation:

-(-1z+9)



We add all the numbers together, and all the variables

15z-(-1z+9)-44=0

We get rid of parentheses

15z+1z-9-44=0

We add all the numbers together, and all the variables

16z-53=0

We move all terms containing z to the left, all other terms to the right

16z=53

z=53/16

z=3+5/16

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