15-c=2(c+3)

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Solution for 15-c=2(c+3) equation: 



15-c=2(c+3)

We move all terms to the left:

15-c-(2(c+3))=0

We add all the numbers together, and all the variables

-1c-(2(c+3))+15=0



We calculate terms in parentheses: -(2(c+3)), so:

2(c+3)

We multiply parentheses

2c+6

Back to the equation:

-(2c+6)



We get rid of parentheses

-1c-2c-6+15=0

We add all the numbers together, and all the variables

-3c+9=0

We move all terms containing c to the left, all other terms to the right

-3c=-9

c=-9/-3

c=+3

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