15-5c(4c-7)=50

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Solution for 15-5c(4c-7)=50 equation: 



15-5c(4c-7)=50

We move all terms to the left:

15-5c(4c-7)-(50)=0

We add all the numbers together, and all the variables

-5c(4c-7)-35=0

We multiply parentheses

-20c^2+35c-35=0

a = -20; b = 35; c = -35;
Δ = b2-4ac
Δ = 352-4·(-20)·(-35)
Δ = -1575
Delta is less than zero, so there is no solution for the equation

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