15-5(4c+-7)=50

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Solution for 15-5(4c+-7)=50 equation: 



15-5(4c+-7)=50

We move all terms to the left:

15-5(4c+-7)-(50)=0

We add all the numbers together, and all the variables

-5(4c-7)+15-50=0

We add all the numbers together, and all the variables

-5(4c-7)-35=0

We multiply parentheses

-20c+35-35=0

We add all the numbers together, and all the variables

-20c=0

c=0/-20

c=0

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