36-5a=-7(1+3a)-5

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Solution for 36-5a=-7(1+3a)-5 equation: 



36-5a=-7(1+3a)-5

We move all terms to the left:

36-5a-(-7(1+3a)-5)=0

We add all the numbers together, and all the variables

-5a-(-7(3a+1)-5)+36=0



We calculate terms in parentheses: -(-7(3a+1)-5), so:

-7(3a+1)-5

We multiply parentheses

-21a-7-5

We add all the numbers together, and all the variables

-21a-12

Back to the equation:

-(-21a-12)



We get rid of parentheses

-5a+21a+12+36=0

We add all the numbers together, and all the variables

16a+48=0

We move all terms containing a to the left, all other terms to the right

16a=-48

a=-48/16

a=-3

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