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15(x+3)=(2x)12
We move all terms to the left:
15(x+3)-((2x)12)=0
determiningTheFunctionDomain 15(x+3)-2x12=0
We add all the numbers together, and all the variables
-2x^12+15(x+3)=0
We multiply parentheses
-2x^12+15x+45=0
We do not support expression: x^12
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