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4/5x-3x+5x=7+8
We move all terms to the left:
4/5x-3x+5x-(7+8)=0
Domain of the equation: 5x!=0We add all the numbers together, and all the variables
x!=0/5
x!=0
x∈R
4/5x-3x+5x-15=0
We add all the numbers together, and all the variables
2x+4/5x-15=0
We multiply all the terms by the denominator
2x*5x-15*5x+4=0
Wy multiply elements
10x^2-75x+4=0
a = 10; b = -75; c = +4;
Δ = b2-4ac
Δ = -752-4·10·4
Δ = 5465
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-75)-\sqrt{5465}}{2*10}=\frac{75-\sqrt{5465}}{20} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-75)+\sqrt{5465}}{2*10}=\frac{75+\sqrt{5465}}{20} $
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