15(x+1)-7(x+9)=4(x-5)

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Solution for 15(x+1)-7(x+9)=4(x-5) equation: 



15(x+1)-7(x+9)=4(x-5)

We move all terms to the left:

15(x+1)-7(x+9)-(4(x-5))=0

We multiply parentheses

15x-7x-(4(x-5))+15-63=0



We calculate terms in parentheses: -(4(x-5)), so:

4(x-5)

We multiply parentheses

4x-20

Back to the equation:

-(4x-20)



We add all the numbers together, and all the variables

8x-(4x-20)-48=0

We get rid of parentheses

8x-4x+20-48=0

We add all the numbers together, and all the variables

4x-28=0

We move all terms containing x to the left, all other terms to the right

4x=28

x=28/4

x=7

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