14y-4=(12+5y)2

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Solution for 14y-4=(12+5y)2 equation: 



14y-4=(12+5y)2

We move all terms to the left:

14y-4-((12+5y)2)=0

We add all the numbers together, and all the variables

14y-((5y+12)2)-4=0



We calculate terms in parentheses: -((5y+12)2), so:

(5y+12)2

We multiply parentheses

10y+24

Back to the equation:

-(10y+24)



We get rid of parentheses

14y-10y-24-4=0

We add all the numbers together, and all the variables

4y-28=0

We move all terms containing y to the left, all other terms to the right

4y=28

y=28/4

y=7

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