-5(4x2)=-2(3+6x)

Solution for -5(4x2)=-2(3+6x) equation:

-5(4x^2)=-2(3+6x)

We move all terms to the left:

-5(4x^2)-(-2(3+6x))=0

We add all the numbers together, and all the variables

-54x^2-(-2(6x+3))=0


We calculate terms in parentheses: -(-2(6x+3)), so:

-2(6x+3)

We multiply parentheses

-12x-6

Back to the equation:

-(-12x-6)


We get rid of parentheses

-54x^2+12x+6=0

a = -54; b = 12; c = +6;
Δ = b2-4ac
Δ = 122-4·(-54)·6
Δ = 1440
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{1440}=\sqrt{144*10}=\sqrt{144}*\sqrt{10}=12\sqrt{10}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(12)-12\sqrt{10}}{2*-54}=\frac{-12-12\sqrt{10}}{-108}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(12)+12\sqrt{10}}{2*-54}=\frac{-12+12\sqrt{10}}{-108}
$