14y+2y(6-y)=14y

Solution for 14y+2y(6-y)=14y equation:

14y+2y(6-y)=14y

We move all terms to the left:

14y+2y(6-y)-(14y)=0

We add all the numbers together, and all the variables

14y+2y(-1y+6)-14y=0

We add all the numbers together, and all the variables

2y(-1y+6)=0

We multiply parentheses

-2y^2+12y=0

a = -2; b = 12; c = 0;
Δ = b2-4ac
Δ = 122-4·(-2)·0
Δ = 144
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{144}=12$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(12)-12}{2*-2}=\frac{-24}{-4}
=+6
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(12)+12}{2*-2}=\frac{0}{-4}
=0
$