8(z-5)=-2(2z-10)

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Solution for 8(z-5)=-2(2z-10) equation: 



8(z-5)=-2(2z-10)

We move all terms to the left:

8(z-5)-(-2(2z-10))=0

We multiply parentheses

8z-(-2(2z-10))-40=0



We calculate terms in parentheses: -(-2(2z-10)), so:

-2(2z-10)

We multiply parentheses

-4z+20

Back to the equation:

-(-4z+20)



We get rid of parentheses

8z+4z-20-40=0

We add all the numbers together, and all the variables

12z-60=0

We move all terms containing z to the left, all other terms to the right

12z=60

z=60/12

z=5

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