14x+3-(3-2x)=-3x+17-2(4x-31)

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Solution for 14x+3-(3-2x)=-3x+17-2(4x-31) equation: 



14x+3-(3-2x)=-3x+17-2(4x-31)

We move all terms to the left:

14x+3-(3-2x)-(-3x+17-2(4x-31))=0

We add all the numbers together, and all the variables

14x-(-2x+3)-(-3x+17-2(4x-31))+3=0

We get rid of parentheses

14x+2x-(-3x+17-2(4x-31))-3+3=0



We calculate terms in parentheses: -(-3x+17-2(4x-31)), so:

-3x+17-2(4x-31)

determiningTheFunctionDomain
-3x-2(4x-31)+17

We multiply parentheses

-3x-8x+62+17

We add all the numbers together, and all the variables

-11x+79

Back to the equation:

-(-11x+79)



We add all the numbers together, and all the variables

16x-(-11x+79)=0

We get rid of parentheses

16x+11x-79=0

We add all the numbers together, and all the variables

27x-79=0

We move all terms containing x to the left, all other terms to the right

27x=79

x=79/27

x=2+25/27

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