(7-2x)+5x=(-4+10x)+6

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Solution for (7-2x)+5x=(-4+10x)+6 equation: 



(7-2x)+5x=(-4+10x)+6

We move all terms to the left:

(7-2x)+5x-((-4+10x)+6)=0

We add all the numbers together, and all the variables

(-2x+7)+5x-((10x-4)+6)=0

We add all the numbers together, and all the variables

5x+(-2x+7)-((10x-4)+6)=0

We get rid of parentheses

5x-2x-((10x-4)+6)+7=0



We calculate terms in parentheses: -((10x-4)+6), so:

(10x-4)+6

We get rid of parentheses

10x-4+6

We add all the numbers together, and all the variables

10x+2

Back to the equation:

-(10x+2)



We add all the numbers together, and all the variables

3x-(10x+2)+7=0

We get rid of parentheses

3x-10x-2+7=0

We add all the numbers together, and all the variables

-7x+5=0

We move all terms containing x to the left, all other terms to the right

-7x=-5

x=-5/-7

x=5/7

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