14k2-67k+63=0

Solution for 14k2-67k+63=0 equation:

14k^2-67k+63=0

a = 14; b = -67; c = +63;
Δ = b2-4ac
Δ = -672-4·14·63
Δ = 961
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$k_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$k_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{961}=31$
$k_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-67)-31}{2*14}=\frac{36}{28}
=1+2/7
$
$k_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-67)+31}{2*14}=\frac{98}{28}
=3+1/2
$