-5=-1/3(c-7)

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Solution for -5=-1/3(c-7) equation:



-5=-1/3(c-7)
We move all terms to the left:
-5-(-1/3(c-7))=0
Domain of the equation: 3(c-7))!=0
c∈R
We multiply all the terms by the denominator
-(-1-5*3(c-7))=0
We calculate terms in parentheses: -(-1-5*3(c-7)), so:
-1-5*3(c-7)
determiningTheFunctionDomain -5*3(c-7)-1
Wy multiply elements
-15c(c-1
Back to the equation:
-(-15c(c-1)
We calculate terms in parentheses: -(-15c(c-1), so:
-15c(c-1
We calculate terms in parentheses: -(-15c(c-1), so:
-15c(c-1
We calculate terms in parentheses: -(-15c(c-1), so:
-15c(c-1
We calculate terms in parentheses: -(-15c(c-1), so:
-15c(c-1
We calculate terms in parentheses: -(-15c(c-1), so:
-15c(c-1
We calculate terms in parentheses: -(-15c(c-1), so:
-15c(c-1
We calculate terms in parentheses: -(-15c(c-1), so:
-15c(c-1
We calculate terms in parentheses: -(-15c(c-1), so:
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We calculate terms in parentheses: -(-15c(c-1), so:
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We calculate terms in parentheses: -(-15c(c-1), so:
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We calculate terms in parentheses: -(-15c(c-1), so:
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We calculate terms in parentheses: -(-15c(c-1), so:
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We calculate terms in parentheses: -(-15c(c-1), so:
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