14=3(q-11)+5

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Solution for 14=3(q-11)+5 equation: 



14=3(q-11)+5

We move all terms to the left:

14-(3(q-11)+5)=0



We calculate terms in parentheses: -(3(q-11)+5), so:

3(q-11)+5

We multiply parentheses

3q-33+5

We add all the numbers together, and all the variables

3q-28

Back to the equation:

-(3q-28)



We get rid of parentheses

-3q+28+14=0

We add all the numbers together, and all the variables

-3q+42=0

We move all terms containing q to the left, all other terms to the right

-3q=-42

q=-42/-3

q=+14

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