(4x-4)+x=21

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Solution for (4x-4)+x=21 equation: 



(4x-4)+x=21

We move all terms to the left:

(4x-4)+x-(21)=0

We add all the numbers together, and all the variables

x+(4x-4)-21=0

We get rid of parentheses

x+4x-4-21=0

We add all the numbers together, and all the variables

5x-25=0

We move all terms containing x to the left, all other terms to the right

5x=25

x=25/5

x=5

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