7(z-2)+4=-3(4-z)

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Solution for 7(z-2)+4=-3(4-z) equation: 



7(z-2)+4=-3(4-z)

We move all terms to the left:

7(z-2)+4-(-3(4-z))=0

We add all the numbers together, and all the variables

7(z-2)-(-3(-1z+4))+4=0

We multiply parentheses

7z-(-3(-1z+4))-14+4=0



We calculate terms in parentheses: -(-3(-1z+4)), so:

-3(-1z+4)

We multiply parentheses

3z-12

Back to the equation:

-(3z-12)



We add all the numbers together, and all the variables

7z-(3z-12)-10=0

We get rid of parentheses

7z-3z+12-10=0

We add all the numbers together, and all the variables

4z+2=0

We move all terms containing z to the left, all other terms to the right

4z=-2

z=-2/4

z=-1/2

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