14=3(f-5)+-1

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Solution for 14=3(f-5)+-1 equation: 



14=3(f-5)+-1

We move all terms to the left:

14-(3(f-5)+-1)=0

We use the square of the difference formula

-(3(f-5)-1)+14=0



We calculate terms in parentheses: -(3(f-5)-1), so:

3(f-5)-1

We multiply parentheses

3f-15-1

We add all the numbers together, and all the variables

3f-16

Back to the equation:

-(3f-16)



We get rid of parentheses

-3f+16+14=0

We add all the numbers together, and all the variables

-3f+30=0

We move all terms containing f to the left, all other terms to the right

-3f=-30

f=-30/-3

f=+10

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