8p2-242=0

Solution for 8p2-242=0 equation:

8p^2-242=0

a = 8; b = 0; c = -242;
Δ = b2-4ac
Δ = 02-4·8·(-242)
Δ = 7744
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{7744}=88$
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-88}{2*8}=\frac{-88}{16}
=-5+1/2
$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+88}{2*8}=\frac{88}{16}
=5+1/2
$