14=-2(21-z)+3(z-4)

Solution for 14=-2(21-z)+3(z-4) equation:

14=-2(21-z)+3(z-4)

We move all terms to the left:

14-(-2(21-z)+3(z-4))=0

We add all the numbers together, and all the variables

-(-2(-1z+21)+3(z-4))+14=0


We calculate terms in parentheses: -(-2(-1z+21)+3(z-4)), so:

-2(-1z+21)+3(z-4)

We multiply parentheses

2z+3z-42-12

We add all the numbers together, and all the variables

5z-54

Back to the equation:

-(5z-54)


We get rid of parentheses

-5z+54+14=0

We add all the numbers together, and all the variables

-5z+68=0

We move all terms containing z to the left, all other terms to the right

-5z=-68

z=-68/-5

z=13+3/5