32x+22=5(6x+4)+2x+2

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Solution for 32x+22=5(6x+4)+2x+2 equation: 



32x+22=5(6x+4)+2x+2

We move all terms to the left:

32x+22-(5(6x+4)+2x+2)=0



We calculate terms in parentheses: -(5(6x+4)+2x+2), so:

5(6x+4)+2x+2

We add all the numbers together, and all the variables

2x+5(6x+4)+2

We multiply parentheses

2x+30x+20+2

We add all the numbers together, and all the variables

32x+22

Back to the equation:

-(32x+22)



We get rid of parentheses

32x-32x-22+22=0

We add all the numbers together, and all the variables

=0

x=0/1

x=0

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