145=x+(x+1)+(x+2)+(x+3)+(x+4)

Solution for 145=x+(x+1)+(x+2)+(x+3)+(x+4) equation:

145=x+(x+1)+(x+2)+(x+3)+(x+4)

We move all terms to the left:

145-(x+(x+1)+(x+2)+(x+3)+(x+4))=0


We calculate terms in parentheses: -(x+(x+1)+(x+2)+(x+3)+(x+4)), so:

x+(x+1)+(x+2)+(x+3)+(x+4)

We get rid of parentheses

x+x+x+x+x+1+2+3+4

We add all the numbers together, and all the variables

5x+10

Back to the equation:

-(5x+10)


We get rid of parentheses

-5x-10+145=0

We add all the numbers together, and all the variables

-5x+135=0

We move all terms containing x to the left, all other terms to the right

-5x=-135

x=-135/-5

x=+27