144=(3x+1)(2x-1)

Solution for 144=(3x+1)(2x-1) equation:

144=(3x+1)(2x-1)

We move all terms to the left:

144-((3x+1)(2x-1))=0

We multiply parentheses ..

-((+6x^2-3x+2x-1))+144=0


We calculate terms in parentheses: -((+6x^2-3x+2x-1)), so:

(+6x^2-3x+2x-1)

We get rid of parentheses

6x^2-3x+2x-1

We add all the numbers together, and all the variables

6x^2-1x-1

Back to the equation:

-(6x^2-1x-1)


We get rid of parentheses

-6x^2+1x+1+144=0

We add all the numbers together, and all the variables

-6x^2+x+145=0

a = -6; b = 1; c = +145;
Δ = b2-4ac
Δ = 12-4·(-6)·145
Δ = 3481
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{3481}=59$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-59}{2*-6}=\frac{-60}{-12}
=+5
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+59}{2*-6}=\frac{58}{-12}
=-4+5/6
$