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w(2w-5)=117
We move all terms to the left:
w(2w-5)-(117)=0
We multiply parentheses
2w^2-5w-117=0
a = 2; b = -5; c = -117;
Δ = b2-4ac
Δ = -52-4·2·(-117)
Δ = 961
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{961}=31$$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-5)-31}{2*2}=\frac{-26}{4} =-6+1/2 $$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-5)+31}{2*2}=\frac{36}{4} =9 $
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