140=x2+5x

Solution for 140=x2+5x equation:

140=x2+5x

We move all terms to the left:

140-(x2+5x)=0

We add all the numbers together, and all the variables

-(+x^2+5x)+140=0

We get rid of parentheses

-x^2-5x+140=0

We add all the numbers together, and all the variables

-1x^2-5x+140=0

a = -1; b = -5; c = +140;
Δ = b2-4ac
Δ = -52-4·(-1)·140
Δ = 585
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{585}=\sqrt{9*65}=\sqrt{9}*\sqrt{65}=3\sqrt{65}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-5)-3\sqrt{65}}{2*-1}=\frac{5-3\sqrt{65}}{-2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-5)+3\sqrt{65}}{2*-1}=\frac{5+3\sqrt{65}}{-2}
$