7(2y-3)=29

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Solution for 7(2y-3)=29 equation: 



7(2y-3)=29

We move all terms to the left:

7(2y-3)-(29)=0

We multiply parentheses

14y-21-29=0

We add all the numbers together, and all the variables

14y-50=0

We move all terms containing y to the left, all other terms to the right

14y=50

y=50/14

y=3+4/7

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