14+x-4+(14+x-4)=x+x+3+(x+x+3)

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Solution for 14+x-4+(14+x-4)=x+x+3+(x+x+3) equation: 



14+x-4+(14+x-4)=x+x+3+(x+x+3)

We move all terms to the left:

14+x-4+(14+x-4)-(x+x+3+(x+x+3))=0

We add all the numbers together, and all the variables

x+(x+10)-(x+x+3+(2x+3))+14-4=0

We add all the numbers together, and all the variables

x+(x+10)-(x+x+3+(2x+3))+10=0

We get rid of parentheses

x+x-(x+x+3+(2x+3))+10+10=0



We calculate terms in parentheses: -(x+x+3+(2x+3)), so:

x+x+3+(2x+3)

determiningTheFunctionDomain
x+x+(2x+3)+3

We add all the numbers together, and all the variables

2x+(2x+3)+3

We get rid of parentheses

2x+2x+3+3

We add all the numbers together, and all the variables

4x+6

Back to the equation:

-(4x+6)



We add all the numbers together, and all the variables

2x-(4x+6)+20=0

We get rid of parentheses

2x-4x-6+20=0

We add all the numbers together, and all the variables

-2x+14=0

We move all terms containing x to the left, all other terms to the right

-2x=-14

x=-14/-2

x=+7

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