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x2+33-14x=0
We add all the numbers together, and all the variables
x^2-14x+33=0
a = 1; b = -14; c = +33;
Δ = b2-4ac
Δ = -142-4·1·33
Δ = 64
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{64}=8$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-14)-8}{2*1}=\frac{6}{2} =3 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-14)+8}{2*1}=\frac{22}{2} =11 $
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