14(x+3)=11(x+2)+80

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Solution for 14(x+3)=11(x+2)+80 equation: 



14(x+3)=11(x+2)+80

We move all terms to the left:

14(x+3)-(11(x+2)+80)=0

We multiply parentheses

14x-(11(x+2)+80)+42=0



We calculate terms in parentheses: -(11(x+2)+80), so:

11(x+2)+80

We multiply parentheses

11x+22+80

We add all the numbers together, and all the variables

11x+102

Back to the equation:

-(11x+102)



We get rid of parentheses

14x-11x-102+42=0

We add all the numbers together, and all the variables

3x-60=0

We move all terms containing x to the left, all other terms to the right

3x=60

x=60/3

x=20

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