7y-38=-2(4-6y)

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Solution for 7y-38=-2(4-6y) equation:



7y-38=-2(4-6y)
We move all terms to the left:
7y-38-(-2(4-6y))=0
We add all the numbers together, and all the variables
7y-(-2(-6y+4))-38=0
We calculate terms in parentheses: -(-2(-6y+4)), so:
-2(-6y+4)
We multiply parentheses
12y-8
Back to the equation:
-(12y-8)
We get rid of parentheses
7y-12y+8-38=0
We add all the numbers together, and all the variables
-5y-30=0
We move all terms containing y to the left, all other terms to the right
-5y=30
y=30/-5
y=-6

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