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14(x+2)-2x=3(4x+3)-10
We move all terms to the left:
14(x+2)-2x-(3(4x+3)-10)=0
We add all the numbers together, and all the variables
-2x+14(x+2)-(3(4x+3)-10)=0
We multiply parentheses
-2x+14x-(3(4x+3)-10)+28=0
We calculate terms in parentheses: -(3(4x+3)-10), so:We add all the numbers together, and all the variables
3(4x+3)-10
We multiply parentheses
12x+9-10
We add all the numbers together, and all the variables
12x-1
Back to the equation:
-(12x-1)
12x-(12x-1)+28=0
We get rid of parentheses
12x-12x+1+28=0
We add all the numbers together, and all the variables
29!=0
There is no solution for this equation
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