14(v+2)-2v=3(4v+1)-8

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Solution for 14(v+2)-2v=3(4v+1)-8 equation: 


Simplifying
14(v + 2) + -2v = 3(4v + 1) + -8

Reorder the terms:
14(2 + v) + -2v = 3(4v + 1) + -8
(2 * 14 + v * 14) + -2v = 3(4v + 1) + -8
(28 + 14v) + -2v = 3(4v + 1) + -8

Combine like terms: 14v + -2v = 12v
28 + 12v = 3(4v + 1) + -8

Reorder the terms:
28 + 12v = 3(1 + 4v) + -8
28 + 12v = (1 * 3 + 4v * 3) + -8
28 + 12v = (3 + 12v) + -8

Reorder the terms:
28 + 12v = 3 + -8 + 12v

Combine like terms: 3 + -8 = -5
28 + 12v = -5 + 12v

Add '-12v' to each side of the equation.
28 + 12v + -12v = -5 + 12v + -12v

Combine like terms: 12v + -12v = 0
28 + 0 = -5 + 12v + -12v
28 = -5 + 12v + -12v

Combine like terms: 12v + -12v = 0
28 = -5 + 0
28 = -5

Solving
28 = -5

Couldn't find a variable to solve for.

This equation is invalid, the left and right sides are not equal, therefore there is no solution.

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