4(3y-2)/5y=2

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Solution for 4(3y-2)/5y=2 equation:


y in (-oo:+oo)

y*((4*(3*y-2))/5) = 2 // - 2

y*((4*(3*y-2))/5)-2 = 0

(4*y*(3*y-2))/5-2 = 0

(4*y*(3*y-2))/5+(-2*5)/5 = 0

4*y*(3*y-2)-2*5 = 0

12*y^2-8*y-10 = 0

12*y^2-8*y-10 = 0

2*(6*y^2-4*y-5) = 0

6*y^2-4*y-5 = 0

DELTA = (-4)^2-(-5*4*6)

DELTA = 136

DELTA > 0

y = (136^(1/2)+4)/(2*6) or y = (4-136^(1/2))/(2*6)

y = (2*34^(1/2)+4)/12 or y = (4-2*34^(1/2))/12

2*(y-((4-2*34^(1/2))/12))*(y-((2*34^(1/2)+4)/12)) = 0

(2*(y-((4-2*34^(1/2))/12))*(y-((2*34^(1/2)+4)/12)))/5 = 0

(2*(y-((4-2*34^(1/2))/12))*(y-((2*34^(1/2)+4)/12)))/5 = 0 // * 5

2*(y-((4-2*34^(1/2))/12))*(y-((2*34^(1/2)+4)/12)) = 0

( y-((2*34^(1/2)+4)/12) )

y-((2*34^(1/2)+4)/12) = 0 // + (2*34^(1/2)+4)/12

y = (2*34^(1/2)+4)/12

( y-((4-2*34^(1/2))/12) )

y-((4-2*34^(1/2))/12) = 0 // + (4-2*34^(1/2))/12

y = (4-2*34^(1/2))/12

y in { (2*34^(1/2)+4)/12, (4-2*34^(1/2))/12 }

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