14(t-1)-2(2t+3)=5(t+3)

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Solution for 14(t-1)-2(2t+3)=5(t+3) equation: 



14(t-1)-2(2t+3)=5(t+3)

We move all terms to the left:

14(t-1)-2(2t+3)-(5(t+3))=0

We multiply parentheses

14t-4t-(5(t+3))-14-6=0



We calculate terms in parentheses: -(5(t+3)), so:

5(t+3)

We multiply parentheses

5t+15

Back to the equation:

-(5t+15)



We add all the numbers together, and all the variables

10t-(5t+15)-20=0

We get rid of parentheses

10t-5t-15-20=0

We add all the numbers together, and all the variables

5t-35=0

We move all terms containing t to the left, all other terms to the right

5t=35

t=35/5

t=7

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