14(b-1)+6=2(7b-4)

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Solution for 14(b-1)+6=2(7b-4) equation: 



14(b-1)+6=2(7b-4)

We move all terms to the left:

14(b-1)+6-(2(7b-4))=0

We multiply parentheses

14b-(2(7b-4))-14+6=0



We calculate terms in parentheses: -(2(7b-4)), so:

2(7b-4)

We multiply parentheses

14b-8

Back to the equation:

-(14b-8)



We add all the numbers together, and all the variables

14b-(14b-8)-8=0

We get rid of parentheses

14b-14b+8-8=0

We add all the numbers together, and all the variables

=0

b=0/1

b=0

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