14(3x-5)=28(x-2)

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Solution for 14(3x-5)=28(x-2) equation:



14(3x-5)=28(x-2)
We move all terms to the left:
14(3x-5)-(28(x-2))=0
We multiply parentheses
42x-(28(x-2))-70=0
We calculate terms in parentheses: -(28(x-2)), so:
28(x-2)
We multiply parentheses
28x-56
Back to the equation:
-(28x-56)
We get rid of parentheses
42x-28x+56-70=0
We add all the numbers together, and all the variables
14x-14=0
We move all terms containing x to the left, all other terms to the right
14x=14
x=14/14
x=1

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