14(3x-5)=-28(x-2)

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Solution for 14(3x-5)=-28(x-2) equation: 



14(3x-5)=-28(x-2)

We move all terms to the left:

14(3x-5)-(-28(x-2))=0

We multiply parentheses

42x-(-28(x-2))-70=0



We calculate terms in parentheses: -(-28(x-2)), so:

-28(x-2)

We multiply parentheses

-28x+56

Back to the equation:

-(-28x+56)



We get rid of parentheses

42x+28x-56-70=0

We add all the numbers together, and all the variables

70x-126=0

We move all terms containing x to the left, all other terms to the right

70x=126

x=126/70

x=1+4/5

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