If it's not what You are looking for type in the equation solver your own equation and let us solve it.
13x^2+10x=0
a = 13; b = 10; c = 0;
Δ = b2-4ac
Δ = 102-4·13·0
Δ = 100
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{100}=10$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(10)-10}{2*13}=\frac{-20}{26} =-10/13 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(10)+10}{2*13}=\frac{0}{26} =0 $
| 5y=2y+7y | | 20=4(2+w | | 20=4(3+u | | 7x=25=88 | | y-3=-2(X+6) | | 4a+3a+2a=180 | | 2x+18=47 | | 2x^2+10=82 | | 41+p-3=180 | | 6w-4+90+7w+3=180 | | 18=u/2+16 | | 3=32x83=x2 | | 3(1-9x)=13x | | 3-5x=40-7x | | 6x+7+8x-5+10x-11=180 | | 2x+5+10-x+35=180 | | w-7.1=184 | | 2x+16+48+90=180 | | x+12+82+62=180 | | 2x+106+31=180 | | 3x-12+33+90=180 | | Y=18x+45 | | 10p+9-11-p=-2(2p+4)-3(2p/2) | | 0.1t^2-10t-62.5=0 | | -2x-7x=-216 | | (3x+15)=(x+45) | | 6y+6y+6y=360 | | (3x+3)=54 | | (3x+3)+54=180 | | (2x+17)=(2x+5) | | (2x+17)+(2x+5)=180 | | (x-18)+(6x+2)=180 |