10p+9-11-p=-2(2p+4)-3(2p/2)

Solution for 10p+9-11-p=-2(2p+4)-3(2p/2) equation:

10p+9-11-p=-2(2p+4)-3(2p/2)

We move all terms to the left:

10p+9-11-p-(-2(2p+4)-3(2p/2))=0

We add all the numbers together, and all the variables

10p-p-(-2(2p+4)-3(+2p/2))+9-11=0

We add all the numbers together, and all the variables

9p-(-2(2p+4)-3(+2p/2))-2=0

We multiply all the terms by the denominator


9p*2))-(-2(2p+2p+4)-3(-2*2))=0

We add all the numbers together, and all the variables

9p*2))-(-2(4p+4)-3(-4))=0

We add all the numbers together, and all the variables

9p*2))-(-2(4p=0

Wy multiply elements

18p^2=0

a = 18; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·18·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$p=\frac{-b}{2a}=\frac{0}{36}=0$