13x-7+2x+16=9(x+1)+6x

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Solution for 13x-7+2x+16=9(x+1)+6x equation: 



13x-7+2x+16=9(x+1)+6x

We move all terms to the left:

13x-7+2x+16-(9(x+1)+6x)=0

We add all the numbers together, and all the variables

15x-(9(x+1)+6x)+9=0



We calculate terms in parentheses: -(9(x+1)+6x), so:

9(x+1)+6x

We add all the numbers together, and all the variables

6x+9(x+1)

We multiply parentheses

6x+9x+9

We add all the numbers together, and all the variables

15x+9

Back to the equation:

-(15x+9)



We get rid of parentheses

15x-15x-9+9=0

We add all the numbers together, and all the variables

=0

x=0/1

x=0

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