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6(x-1)+10=3(2x+2)+5
We move all terms to the left:
6(x-1)+10-(3(2x+2)+5)=0
We multiply parentheses
6x-(3(2x+2)+5)-6+10=0
We calculate terms in parentheses: -(3(2x+2)+5), so:We add all the numbers together, and all the variables
3(2x+2)+5
We multiply parentheses
6x+6+5
We add all the numbers together, and all the variables
6x+11
Back to the equation:
-(6x+11)
6x-(6x+11)+4=0
We get rid of parentheses
6x-6x-11+4=0
We add all the numbers together, and all the variables
-7!=0
There is no solution for this equation
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