13x-2(3x-4)=4(x+4)-12

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Solution for 13x-2(3x-4)=4(x+4)-12 equation: 



13x-2(3x-4)=4(x+4)-12

We move all terms to the left:

13x-2(3x-4)-(4(x+4)-12)=0

We multiply parentheses

13x-6x-(4(x+4)-12)+8=0



We calculate terms in parentheses: -(4(x+4)-12), so:

4(x+4)-12

We multiply parentheses

4x+16-12

We add all the numbers together, and all the variables

4x+4

Back to the equation:

-(4x+4)



We add all the numbers together, and all the variables

7x-(4x+4)+8=0

We get rid of parentheses

7x-4x-4+8=0

We add all the numbers together, and all the variables

3x+4=0

We move all terms containing x to the left, all other terms to the right

3x=-4

x=-4/3

x=-1+1/3

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