13x-2(3x+5)=6+4(x-3)

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Solution for 13x-2(3x+5)=6+4(x-3) equation: 



13x-2(3x+5)=6+4(x-3)

We move all terms to the left:

13x-2(3x+5)-(6+4(x-3))=0

We multiply parentheses

13x-6x-(6+4(x-3))-10=0



We calculate terms in parentheses: -(6+4(x-3)), so:

6+4(x-3)

determiningTheFunctionDomain
4(x-3)+6

We multiply parentheses

4x-12+6

We add all the numbers together, and all the variables

4x-6

Back to the equation:

-(4x-6)



We add all the numbers together, and all the variables

7x-(4x-6)-10=0

We get rid of parentheses

7x-4x+6-10=0

We add all the numbers together, and all the variables

3x-4=0

We move all terms containing x to the left, all other terms to the right

3x=4

x=4/3

x=1+1/3

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