2(y-5+3)=-3(2+y-5)

Solution for 2(y-5+3)=-3(2+y-5) equation:

2(y-5+3)=-3(2+y-5)

We move all terms to the left:

2(y-5+3)-(-3(2+y-5))=0

We add all the numbers together, and all the variables

2(y-2)-(-3(y-3))=0

We multiply parentheses

2y-(-3(y-3))-4=0


We calculate terms in parentheses: -(-3(y-3)), so:

-3(y-3)

We multiply parentheses

-3y+9

Back to the equation:

-(-3y+9)


We get rid of parentheses

2y+3y-9-4=0

We add all the numbers together, and all the variables

5y-13=0

We move all terms containing y to the left, all other terms to the right

5y=13

y=13/5

y=2+3/5