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13w-2/3w=16
We move all terms to the left:
13w-2/3w-(16)=0
Domain of the equation: 3w!=0We multiply all the terms by the denominator
w!=0/3
w!=0
w∈R
13w*3w-16*3w-2=0
Wy multiply elements
39w^2-48w-2=0
a = 39; b = -48; c = -2;
Δ = b2-4ac
Δ = -482-4·39·(-2)
Δ = 2616
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{2616}=\sqrt{4*654}=\sqrt{4}*\sqrt{654}=2\sqrt{654}$$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-48)-2\sqrt{654}}{2*39}=\frac{48-2\sqrt{654}}{78} $$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-48)+2\sqrt{654}}{2*39}=\frac{48+2\sqrt{654}}{78} $
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