2(3y+10)=28

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Solution for 2(3y+10)=28 equation: 



2(3y+10)=28

We move all terms to the left:

2(3y+10)-(28)=0

We multiply parentheses

6y+20-28=0

We add all the numbers together, and all the variables

6y-8=0

We move all terms containing y to the left, all other terms to the right

6y=8

y=8/6

y=1+1/3

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