13r-3(r+3)=4(3r-4)-5

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Solution for 13r-3(r+3)=4(3r-4)-5 equation: 



13r-3(r+3)=4(3r-4)-5

We move all terms to the left:

13r-3(r+3)-(4(3r-4)-5)=0

We multiply parentheses

13r-3r-(4(3r-4)-5)-9=0



We calculate terms in parentheses: -(4(3r-4)-5), so:

4(3r-4)-5

We multiply parentheses

12r-16-5

We add all the numbers together, and all the variables

12r-21

Back to the equation:

-(12r-21)



We add all the numbers together, and all the variables

10r-(12r-21)-9=0

We get rid of parentheses

10r-12r+21-9=0

We add all the numbers together, and all the variables

-2r+12=0

We move all terms containing r to the left, all other terms to the right

-2r=-12

r=-12/-2

r=+6

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